Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > Consider the following C code:#include<std...
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Consider the following C code:
#include<stdio.h>
int main()
{
int a[n];
int i, j, n, count = 0;
for(i=0; i < n; i++)
{
for(j=i+1; j < n; j++)
{
if(a[i] == a[j])
{
count++;
break;
}
}
}
printf("%d", count);
return 0;
}
int main()
{
int a[n];
int i, j, n, count = 0;
for(i=0; i < n; i++)
{
for(j=i+1; j < n; j++)
{
if(a[i] == a[j])
{
count++;
break;
}
}
}
printf("%d", count);
return 0;
}
If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.
Correct answer is '4'. Can you explain this answer?
Most Upvoted Answer
Consider the following C code:#include<stdio.h>int main(){int a[...
Understanding the Code
The provided C code is designed to count duplicate elements in an array. Let's break down how it works with the given array.
Array Initialization
- The array `a` contains the elements: 56, 2, 18, 56, 2, 11, 2, 18, 12.
- The variable `n` should hold the size of the array, which is 9 in this case.
Counting Duplicates
- The outer loop iterates through each element of the array using the index `i`.
- The inner loop checks subsequent elements using the index `j` (starting from `i+1`).
- If a duplicate is found (`a[i] == a[j]`), the `count` is incremented by 1, and the inner loop breaks to avoid counting the same duplicate multiple times.
Identifying Duplicates
- For the given array:
- First 56 (at index 0) is checked against 56 (at index 3) → count = 1
- First 2 (at index 1) is checked against 2 (at index 4) and 2 (at index 6) → count = 2 (breaks after finding the first match)
- First 18 (at index 2) is checked against 18 (at index 7) → count = 3
- The rest (11, 12) have no duplicates after them.
Final Count
- The total count of duplicate elements found is 4, as there are three unique duplicates (56, 2, 18), and the count includes the first occurrences of each duplicate.
Conclusion
- The program finally prints the value of `count`, which is 4, indicating that there are 4 duplicates in total across the elements checked.
The provided C code is designed to count duplicate elements in an array. Let's break down how it works with the given array.
Array Initialization
- The array `a` contains the elements: 56, 2, 18, 56, 2, 11, 2, 18, 12.
- The variable `n` should hold the size of the array, which is 9 in this case.
Counting Duplicates
- The outer loop iterates through each element of the array using the index `i`.
- The inner loop checks subsequent elements using the index `j` (starting from `i+1`).
- If a duplicate is found (`a[i] == a[j]`), the `count` is incremented by 1, and the inner loop breaks to avoid counting the same duplicate multiple times.
Identifying Duplicates
- For the given array:
- First 56 (at index 0) is checked against 56 (at index 3) → count = 1
- First 2 (at index 1) is checked against 2 (at index 4) and 2 (at index 6) → count = 2 (breaks after finding the first match)
- First 18 (at index 2) is checked against 18 (at index 7) → count = 3
- The rest (11, 12) have no duplicates after them.
Final Count
- The total count of duplicate elements found is 4, as there are three unique duplicates (56, 2, 18), and the count includes the first occurrences of each duplicate.
Conclusion
- The program finally prints the value of `count`, which is 4, indicating that there are 4 duplicates in total across the elements checked.
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Community Answer
Consider the following C code:#include<stdio.h>int main(){int a[...
The correct code is:
#include<stdio.h>
int main()
{
int a[9]={56,2,18,56,2,11,2,18,12};
int i, j, n=9, count = 0;
for(i=0; i< n; i++)
{
for(j=i+1; j< n; j++)
{
if(a[i] == a[j])
{
count++;
break;
}
}
}
printf("%d", count);
return 0;
}
In the above C code, variable count keeps track of duplicate elements. The second loop starts from i +1 because there is a need to search for duplicate elements in the next subsequent elements, from the current element. The body of the inner loop check for a duplicate element. If a duplicate element is found then increment the duplicate count. Also, terminate the inner loop if a duplicate element is found.
56 appears 2 times.
2 appears 3 times.
18 appears 2 times.
11 appears 1 time.
12 appears 1 time.
Hence, the correct answer is 4.
int main()
{
int a[9]={56,2,18,56,2,11,2,18,12};
int i, j, n=9, count = 0;
for(i=0; i< n; i++)
{
for(j=i+1; j< n; j++)
{
if(a[i] == a[j])
{
count++;
break;
}
}
}
printf("%d", count);
return 0;
}
In the above C code, variable count keeps track of duplicate elements. The second loop starts from i +1 because there is a need to search for duplicate elements in the next subsequent elements, from the current element. The body of the inner loop check for a duplicate element. If a duplicate element is found then increment the duplicate count. Also, terminate the inner loop if a duplicate element is found.
56 appears 2 times.
2 appears 3 times.
18 appears 2 times.
11 appears 1 time.
12 appears 1 time.
Hence, the correct answer is 4.
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Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer?
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Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer?.
Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider the following C code:#include<stdio.h>int main(){int a[n];int i, j, n, count = 0;for(i=0; i < n; i++){for(j=i+1; j < n; j++){if(a[i] == a[j]){count++;break;}}}printf("%d", count);return 0;}If array a contains 56,2,18,56,2,11,2,18,12 then output of the above code is _________.Correct answer is '4'. Can you explain this answer?.
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